Allen named the AFC Offensive Player of the Week

Josh Allen accounted for four total touchdowns against the Dolphins this past Sunday in Miami

Brayton Wilson
November 20, 2019 - 9:20 am

For the second time in his young NFL career, Buffalo Bills quarterback Josh Allen has been named as the AFC Offensive Player of the Week.

The National Football League gave out its weekly honors and Allen was selected as the AFC Offensive Player of the Week for his four-touchdown performance this past week against the Miami Dolphins at Hard Rock Stadium in South Florida.

Allen had, arguably, his best performance of the season on Sunday, going 21-for-33 passing (63.6%) for 256 yards and three touchdowns. He also had 56 yards rushing on the ground and a touchdown to help the Bills to a 37-20 win to improve to 7-3 on the season.

So far through 10 games this season, Allen has completed 60.3% of his passes (191-for-317) for 2,175 yards and 13 touchdowns. Allen has already surpassed his passing marks from his rookie season, where he completed just 52.8% of his passes (169-for-320) for 2,074 yards and 10 touchdowns.

Allen has also completed three fourth quarter comebacks for the Bills, as well as four game-winning drives this season against the New York Jets, Cincinnati Bengals, Tennessee Titans, and the Dolphins in Week 7.

The Bills are back in action this Sunday at New Era Field against the 3-7 Denver Broncos.

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